Question

A current of $5\pm 0.5\text{A}$ flows through a metallic conductor of resistance $10\pm 0.1\Omega$ when a potential difference across the wire is $50\pm$$\text{V}$.

Answer 1

Given:
$I=5\pm 0.5\text{A};R=10\pm 0.1\Omega$

From Ohm's law,

$V=IR$

$V=5\times 10=50\text{V}$

Now, error in measurement of potential difference will be,

$\frac{\Delta V}{V}=\frac{\Delta I}{I}+\frac{\Delta R}{R}$

$\frac{\Delta V}{50}=\frac{0.5}{5}+\frac{0.1}{10}$

$\Rightarrow \Delta V=5.5$

Therefore, effective voltage will be

$V=50\pm 5.5\text{V}$