A current of 5A flow for half an hour through an electric bulb with internal resistance of 20 ohm Calculate the electrical energy dissipated.

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Solution

Dear Student ,
$H = I^{2} R t = 25 \times 20 \times 30 \times 60 = 900000 J$
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A current of 5A flow for half an hour through an electric bulb with internal resistance of 20 ohm Calculate the electrical energy dissipated.

Dear Student , H=I2Rt=25×20×30×60=900000 J Regards

Dear Student ,
$H = I^{2} R t = 25 \times 20 \times 30 \times 60 = 900000 J$
Regards