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Question

A curve has equation y=(2x1)1+2x. x12
Find dydx and d2ydx2.

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Solution

y=(2x1)1+2x

dydx=ddx(2x1)1+2x

dydx=2(2x1)2+2

d2ydx2=ddx2(2x1)2+2

d2ydx2=8(2x1)3.

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