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A cyclic proc...

Question

A cyclic process for 1 mole of an ideal gas is shown in the figure in the $V - T$ diagram. The work done in $A B, B C$ and $C A$ respectively is

A

0, R T^{2} ln (\frac{V_{1}}{V_{2}}), R (T_{1} - T_{2})

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B

R (T_{1} - T_{2}), 0, R T_{1} ln (\frac{V_{1}}{V_{2}})

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C

0, R T_{2} ln (\frac{V_{2}}{V_{1}}), R (T_{1} - T_{2})

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D

0, R T_{2} ln (\frac{V_{1}}{V_{2}}), R (T_{2} - T_{1})

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Solution

The correct option is C $0, R T_{2} ln (\frac{V_{2}}{V_{1}}), R (T_{1} - T_{2})$

$W_{A B} = 0$ (Constant volume process.)

$W_{B C} \to i s o t h e r m a l = R T ln \frac{V_{2}}{V_{1}}$

$W_{C A} \to i s o b a r i c = - P (V_{C} - V_{A}) = - R (T_{2} - T_{1})$

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