A cyclist starts from centre O of a circular park of radius 1km and moves along the path OPRQO as shown in figure. If the maintains constant speed of $10 m s^{- 1}$ , what is his acceleration at point R?

$10 m s^{- 2}$

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$0.1 m s^{- 2}$

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$0.01 m s^{- 2}$

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$1 m s^{- 2}$

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Solution

The correct option is B
$0.1 m s^{- 2}$

$a_{c} = \frac{v^{2}}{r} = \frac{(10 m s^{- 1})^{2}}{1000 m} = 0.1 m s^{- 2}$

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A cyclist starts from centre O of a circular park of radius 1km and moves along the path OPRQO as shown in figure. If the maintains constant speed of 10ms−1, what is his acceleration at point R?

The correct option is B 0.1 ms−2 ac=v2r=(10ms−1)21000m=0.1ms−2

A cyclist starts from centre O of a circular park of radius 1km and moves along the path OPRQO as shown in figure. If the maintains constant speed of $10 m s^{- 1}$ , what is his acceleration at point R?

The correct option is B
$0.1 m s^{- 2}$

$a_{c} = \frac{v^{2}}{r} = \frac{(10 m s^{- 1})^{2}}{1000 m} = 0.1 m s^{- 2}$