Question

# A Cyclist Turns Around A Curve At $15Km/hr$ If He Turns At Double The Speed The Tendency To Overturn Is :

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Solution

## Formula : We know centrifugal force , $F=\frac{m{v}^{2}}{r}$where$v=$velocity of the object$m=$ mass of the object$r=$turning radiusAs the mass and turning radius does not change in this case, we consider them as constant. Thus we can say thatCentrifugal force, $\mathrm{F}=\mathrm{\alpha }{\mathrm{v}}^{2}\left(\mathrm{where}\mathrm{a}=\frac{\mathrm{m}}{\mathrm{r}}=\mathrm{constant}\right)$Now, as per the question, if the velocity of the cyclist is doubled, then its tendency to overturn will be increased by four times.Hence, If a cyclist turns around a curve at $15\mathrm{Km}/\mathrm{hr}$ and if he turns at double the speed , the tendency to overturn will be increased by four times.

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