A cyclist turns around a curve at 15 miles/hour. If he turns at double the speed, the tendency to overturn is

Doubled

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Quadrupled

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Halved

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Unchanged

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Solution

The correct option is B
Quadrupled

F = $\frac{m v^{2}}{r}$ $\Rightarrow$ F $\propto$ $v^{2}$ .If v becomes double then F.

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Similar questions

A cyclist turns around a curve at 15 miles/hour. If he turns at double the speed, the tendency to overturn is

15

20

10 m

10 m / s

g = 10 m / s^{2}

1 \frac{1}{2}

1 \frac{1}{2}

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