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Raoult's Law

A cylinder co...

Question

A cylinder contains gas at a pressure of 2.5 atm. Due to leakage, the pressure falls to 2 atm, after sometime. The percentage of the gas which is leaked out is

A

40

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B

15

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C

20

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D

25

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Solution

The correct option is C 20
$\frac{P_{1}}{d_{1}} = \frac{P_{2}}{d_{2}} \frac{2.5}{d_{1}} = \frac{2}{d_{2}} d_{2} = 0.8 \times d_{1}$
Volume escaped= $Δ d = (1 - 0.8) d_{1} = 0.2 d_{1} P e r c e n t a g e d e c r e a s e, \frac{Δ d}{d_{1}} \times 100 = 20$

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