Question

A cylinder of mass 5 kg is held in vertical position. If the height of the cylinder is 6 cm and radius of cross section is 4 cm then find the pressure acting on its bottom surface.

Answer 1

Given :
$mass=5kg$
$height=6cm$
$radius=4cm$
Pressure on bottom surface
$=\frac{Thrust}{\text{area of bottom surface}}=\frac{mg}{\pi r^2}$

$=\frac{5\times 10}{(\frac{22}{7}\times (0.04{)}^2)}=0.9744\times {10}^{4}Pa.$