Question

A cylinder of mass $5kg$ is held in vertical position. If the height of the cylinder is $6cm$ and radius of cross section is $4cm$ then find the pressure acting on its bottom surface.

Answer 1

Weight of cylinder is $W=5\times g=50N$ , $g=10m/s^2$

Cross section area $A=\pi r^2=16\pi c{m}^2=16\times {10}^{-4}\pi m^2$

Pressure, $P=\frac{weight}{area}=\frac{50}{16\times {10}^{-4}\pi }$

$P=0.97\times {10}^{4}N{m}^{-2}$