Question

a cylinder of radius r and length l is placed in a uniform electric field parallel to the cylindrical axis. the outward flux over the surface of the surface of the cylinder is given by​

Answer 1

Dear Student ,
Here in this case ,
$$\begin{gathered} \int \overrightarrow{E}·d\overrightarrow{S}=\frac{Q}{{\epsilon }_0} \\ \Rightarrow E\int dS=\frac{Q}{{\epsilon }_0} \\ \Rightarrow E\times 2\pi rl=\frac{Q}{{\epsilon }_0} \\ Nowas,flux=\varphi =E\times 2\pi rlforacylinderoverthesurfaceofthecylinderso, \\ flux,\varphi =\frac{Q}{{\epsilon }_0}. \end{gathered}$$
Regards