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Question

A cylinder rolls down an inclined plane of inclination 30, the acceleration of cylinder is

A
g3
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B
g
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C
g2
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D
2g3
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Solution

The correct option is B g3
Remember that acceleration of a cylinder down a smooth inclined plane is
a=gsinθ(1+ImR2) where I=mR22 is the moment of
Inertia for
cylinder a=gsin30(1+mR22×1mR2)=g×121+12=g3
230173_205180_ans.png

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