Question

A cylinder rolls down an inclined, plane of inclination $30$, the acceleration of cylinder is

• A. $\frac{g}{3}$
• B. $g$
• C. $\frac{g}{2}$
• D. $\frac{g}{6}$

Answer 1

The correct option is D $\frac{g}{6}$

$a=\frac{gsin\theta }{1+\frac{I}{m{R}^2}}$

put $I=\frac{m{R}^2}{2}$ (cylinder)

$\theta ={30}^{\circ }$

we get $a=\frac{g/2}{1+2}=g/6$