A cylindrical drum which is $32$ cm in diameter and $28$ cm in height contains water to a depth of $18$ cm. A solid sphere of radius $8$ cm is placed in the drum. How for below the top of the drum is the level of water?

8.5

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10.5

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19.5

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none

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Solution

The correct option is A $8.5$ cm
volume of sphere = volume of water raised
$\frac{4}{3} π (8)^{3} = π \times (16)^{2} \times x$
$\Rightarrow x = 1.5 c m$
Level of water below the top $= 28 - (18 + 1.5)$
$= 8.5 c m$

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A cylindrical drum which is 32 cm in diameter and 28 cm in height contains water to a depth of 18 cm. A solid sphere of radius 8cm is placed in the drum. How for below the top of the drum is the level of water?

The correct option is A 8.5 cmvolume of sphere = volume of water raised43π(8)3=π×(16)2×x⇒x=1.5cmLevel of water below the top =28−(18+1.5)=8.5cm

A cylindrical drum which is $32$ cm in diameter and $28$ cm in height contains water to a depth of $18$ cm. A solid sphere of radius $8$ cm is placed in the drum. How for below the top of the drum is the level of water?

The correct option is A $8.5$ cm
volume of sphere = volume of water raised
$\frac{4}{3} π (8)^{3} = π \times (16)^{2} \times x$
$\Rightarrow x = 1.5 c m$
Level of water below the top $= 28 - (18 + 1.5)$
$= 8.5 c m$