A cylindrical jar is $20 c m$ high with internal diameter $7 c m$ . An iron cube of edge $5 c m$ is immersed in the jar completely in . the water which was originally $12 c m$ high. Find the rise inthe level of water.

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Solution

Volume of water displaced $=$ Volume of the cube.
The radius of the cylinder $= \frac{7}{2} = 3.5$ cm
$\Rightarrow π r^{2} h = 125$
$\Rightarrow \frac{22}{7} \times {3.5}^{2} h = 125$
$\Rightarrow 38.5 h = 125$
$\Rightarrow h = \frac{125}{38.5} = 3.25$ cm
The water will rise by $3.25$ cm
And the new height of water will be $12 + 3.25 = 15.25$ cm.

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A cylindrical jar is 20cm high with internal diameter 7cm. An iron cube of edge 5cm is immersed in the jar completely in . the water which was originally 12cm high. Find the rise inthe level of water.

Volume of water displaced=Volume of the cube.The radius of the cylinder=72=3.5cm⇒πr2h=125⇒227×3.52h=125⇒38.5h=125⇒h=12538.5=3.25cmThe water will rise by 3.25cmAnd the new height of water will be 12+3.25=15.25cm.

A cylindrical jar is $20 c m$ high with internal diameter $7 c m$ . An iron cube of edge $5 c m$ is immersed in the jar completely in . the water which was originally $12 c m$ high. Find the rise inthe level of water.