Question

A cylindrical vessel filled with water is released on an inclined surface of angle $\theta$ as shown in figure. The friction coefficient of surface with vessel is $\mu (<tan\theta )$. Then the constant angle made by the surface of water with the incline will be

• A. $ta{n}^{-1}\left(\mu \right)$
• B. $\theta -ta{n}^{-1}\left(\mu \right)$
• C. $\theta +ta{n}^{-1}\left(\mu \right)$
• D. $co{t}^{-1}\mu$

Answer 1

The correct option is A

$ta{n}^{-1}\left(\mu \right)$

$tan\alpha =\frac{\mu gcos\theta }{gcos\theta }$

$\alpha =ta{n}^{-1}\left(\mu \right)$