A cylindrical vessel of base radius $14 c m$ is filled with water to some height. If a rectangular solid of dimensions $22 c m \times 7 c m \times 5 c m$ is immersed in it, what is the rise in water level?

0.5 c m

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1.0 c m

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1.25 c m

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1.5 c m

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Solution

The correct option is C $1.25 c m$
Rise in vol. of water $=$ vol. of block
$\Rightarrow π r^{2} h = l b h$
$\Rightarrow π (14)^{2} \times h = 22 \times 7 \times 5 \Rightarrow h = 1.25 c m$

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A cylindrical vessel of base radius 14cm is filled with water to some height. If a rectangular solid of dimensions 22cm×7cm×5cm is immersed in it, what is the rise in water level?

The correct option is C 1.25cmRise in vol. of water = vol. of block⇒πr2h=lbh⇒π(14)2×h=22×7×5⇒h=1.25cm

A cylindrical vessel of base radius $14 c m$ is filled with water to some height. If a rectangular solid of dimensions $22 c m \times 7 c m \times 5 c m$ is immersed in it, what is the rise in water level?

The correct option is C $1.25 c m$
Rise in vol. of water $=$ vol. of block
$\Rightarrow π r^{2} h = l b h$
$\Rightarrow π (14)^{2} \times h = 22 \times 7 \times 5 \Rightarrow h = 1.25 c m$