Question

A dealer bought two tanks for rupees 3120. He sold one at a loss of $15\%$ and another at profit of $36\%$. He found that the selling price of both the tanks was same. What was the cost price of each tank.

Answer 1

Let the cost price of both the tanks be x and y respectively.
Given : The sum of cost prices of both tanks is 3120
Thus,
x+y= 3120 .............(1)
1st tank was sold at a discount of $15\%$
SP of the 1st tank= $x-\left(\frac{15x}{100}\right)=0.85x$
2nd tank was sold at a profit of $36\%$
SP of second tank= y+(36y/100)= 1.36y
given that the SP of both the tanks is same
0.85x= 1.36y
x=1.6y
Substituting in (1)
1.6y + y= 3120
2.6y= 3120
y= 1200
x= 1.6y= 1920