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Byju's Answer
Standard X
Mathematics
Solving a Quadratic Equation by Factorization Method
A dealer sell...
Question
A dealer sells a toy for Rs.
24
and gains as much percent as the cost price of the toy. Find the cost price of the toy.
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Solution
Let the cost price of the toy be Rs.
x
.
Then g
ain
x
% Gain
R
s
.
(
x
×
x
100
)
=
R
s
.
x
2
100
S
.
P
=
C
.
P
+
G
a
i
n
=
x
+
x
2
100
But
S
.
P
=
R
s
.
24
⇒
x
+
x
2
100
=
24
⇒
100
x
+
x
2
=
2400
⇒
x
2
+
100
x
−
2400
=
0
⇒
x
2
+
120
x
−
20
x
−
2400
=
0
⇒
x
(
x
+
120
)
−
20
(
x
+
120
)
=
0
⇒
(
x
+
120
)
(
x
−
20
)
=
0
⇒
x
=
20
,
−
120
⇒
x
=
20
Hence the cost price of the toy is Rs.
20
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A dealer sells an article for Rs. 24 and gains as much percent as the cost price of the article. Find the cost price of the article.