A design on the wall of room consists of $1000$ tiles of the shape of parallelogram. If altitude and the base of tiles are $10 c m a n d 4 c m$ respectively, find the cost of polishing the design at the rate of $R s . 1.50$ per $c m^{2}$ .

R s . 500

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R s . 300

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R s . 60000

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R s . 400

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Solution

The correct option is C $R s . 60000$
Area of tiles $=$ $b \times h = 10 \times 4 = 40 {c m}^{2}$
Area of design $=$ 1000 $\times$ 40 = $40000$ ${c m}^{2}$
Therefore, cost of polishing $=$ Rs. $(1.50 \times 40000)$
$=$ Rs. $60000$

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A design on the wall of room consists of 1000 tiles of the shape of parallelogram. If altitude and the base of tiles are 10cmand4cm respectively, find the cost of polishing the design at the rate of Rs.1.50 per cm2.

The correct option is C Rs.60000Area of tiles = b×h=10×4=40cm2Area of design = 1000 × 40 = 40000 cm2Therefore, cost of polishing = Rs. (1.50×40000) = Rs. 60000

A design on the wall of room consists of $1000$ tiles of the shape of parallelogram. If altitude and the base of tiles are $10 c m a n d 4 c m$ respectively, find the cost of polishing the design at the rate of $R s . 1.50$ per $c m^{2}$ .

The correct option is C $R s . 60000$
Area of tiles $=$ $b \times h = 10 \times 4 = 40 {c m}^{2}$
Area of design $=$ 1000 $\times$ 40 = $40000$ ${c m}^{2}$
Therefore, cost of polishing $=$ Rs. $(1.50 \times 40000)$
$=$ Rs. $60000$