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Question

A deuterium reaction that occurs in a hypothetical experimental fusion reactor occurs in two stages
(i) two deuterium (1D2) nuclei fuse together to form a tritium nucleus, with a proton as a by-product: D(D,p)T.
(ii) a tritium nucleus fuses with another deuterium nucleus to form a (2He4) nucleus with neutron as a by-product T(D,n)2He4.
Compute (a) the energy released in each of two the stages and the energy released in the combined reaction.
(b) the energy released per deuterium nucleus.
Given (1D2)=2.014102 a.m.u
1T3=3.016049a.m.u
2He4=4.002603a.m.u
1H1=1.007825a.m.u
0n1=1.008665a.m.u

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Solution

(a) (i) The reaction is
1D2+1D21T3+1P1E1
Δm=[2(2.014102)3.0160491.007825]=0.00433
Energy released, E1=0.00433×931 MeV
=4.031 MeV
(ii) 1T3+1D22He4+0n1+E2
Δm=[(3.016049+2.014102)(4.002603+1.008665)]=0.0188a.m.u
Energy released E2=0.01888×931 MeV =17.580 MeV
Total energy released in both processes
=17.580+4.031=21.611 MeV
(b) Energy released per 1D2=21.6113=7.206 MeV

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