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Question

Two protons and two neutrons combine to form a nucleus of 2He4. Find the energy released during the process. Take masses of proton, neutron and helium nuclues as 1.007u,1.009u,4.002u respectively.

A
27.94 MeV
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B
84.67 MeV
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C
94.82 MeV
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D
24.12 MeV
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Solution

The correct option is A 27.94 MeV
The nuclear reaction is 21p1+20n12He4
First, let us find mass defect and then energy.
The mass of 2p and 2n is (2×1.007+2×1.009)=2×2.016=4.032u.
The mass of helium is =4.002u.
The mass defect =4.0324.002=0.030u.
1u liberates 931.5MeV of energy. The energy equivalent to 0.030u=0.03×931.5=27.94MeV.
The above nuclear reaction is called fusion as lighter nuclei combine together to form a single nuclei.

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