You visited us 1 times! Enjoying our articles? Unlock Full Access!

Binding Energy

The masses of...

Question

The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu. The binding energy of the helium nucleus will be [1 amu= 931 MeV]

28.4 MeV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

20.8 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

27.3 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14.2 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 28.4 MeV
Helium nucleus consist of two neutrons and two protons.
So binding energy $E = Δ m \times 931 M e V$
$\Rightarrow E = (2 \times m_{p} + 2 m_{n} - M) \times 931 M e V = (2 \times 1.0073 + 2 \times 1.0087 - 4.0015) \times 931 = 28.4 M e V$

Suggest Corrections

Similar questions

The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu, the binding energy of the helium nucleus will be [1 amu= 931 MeV]

Q. The masses of neutron and proton are

1.0087 a . m . u .

and

1.0073 a . m . u .

respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass

4.0015 a . m . u

, then the binding energy fo the helium nucleus will be: (

1 a . m . u . = 931 M e V

)

Q. The binding energy of an

α

-particle is
(Given that mass of proton

=

1.0073

amu, mass of neutron

=

1.0087

amu, and mass of

α

-particle

=

4.0015

amu)

Q. Find the binding energy of an

α -

particle from the following data.
Mass of the helium nucleus

= 4.001265 a m u

Mass of proton

= 1.007277 a m u

Mass of neutron

= 1.00866 a m u

(take

1 a m u = 931.4813 M e V)

Join BYJU'S Learning Program

The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu. The binding energy of the helium nucleus will be [1 amu= 931 MeV]

The correct option is A 28.4 MeV Helium nucleus consist of two neutrons and two protons. So binding energy E=Δm×931MeV ⇒ E=(2×mp+2mn−M)×931MeV=(2×1.0073+2×1.0087−4.0015)×931=28.4MeV

The correct option is A 28.4 MeV
Helium nucleus consist of two neutrons and two protons.
So binding energy $E = Δ m \times 931 M e V$
$\Rightarrow E = (2 \times m_{p} + 2 m_{n} - M) \times 931 M e V = (2 \times 1.0073 + 2 \times 1.0087 - 4.0015) \times 931 = 28.4 M e V$