A diatomic gas molecule has translational, rotational and vibrational degrees of freedom. Then CpCv is
A
1.67
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B
2.14
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C
1.29
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D
1.33
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Solution
The correct option is D1.33 The diatomic molecule has total 6 degress of freedom(3 translational, 2 rotational and 1 vibrational) Now Cp is given as (1+f2)R=(1+62)R=4R and Cv is given as f2R=62R=3R Thus we get CpCv=43=1.33