Question

A dice is thrown 50 times and the outcomes are recorded as shown below.

Outcome	1	2	3	4	5	6
No. of times	11	9	8	5	7	10

If a dice is thrown at random, what is the probability of getting 8?
(a) $\frac{1}{5}$

(b) $\frac{3}{50}$

(c) $\frac{1}{3}$

(d) 0

Answer 1

(d) 0

Explanation:
Total number of trials = 50
Number of times 8 appears = 0
P(getting 8) = $\frac{\mathrm{Number}\mathrm{of}\mathrm{times}8\mathrm{appears}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{tr}\text{ia}\mathrm{ls}}=\frac{0}{50}$ = 0

(Remark: A dice is marked from 1 to 6. So, it is impossible to get 8 and probability of an impossible event is 0.)