Question

A dice is thrown once. Find the probability of the event $E_2$ such that outcome is odd no.

• A. $\frac{1}{3}$
• B. $\frac{1}{4}$
• C. $\frac{1}{2}$
• D. $\frac{1}{6}$

Answer 1

The correct option is C $\frac{1}{2}$

A dice is thrown once.

So, possible outcomes are $1,2,3,4,5,6$.

Among them odd numbers are $1,3,5$.

Thus $n\left(E_2\right)=3$ and $n\left(S\right)=6$

Therefore, $P\left(E_2\right)=\frac{n\left(E_2\right)}{n\left(S\right)}=\frac{3}{6}=\frac{1}{2}$.