Question

A fair dice is thrown once. Find the probability of the event such that the outcome of the event is multiple of 5.

• A. $\frac{1}{2}$
• B. $\frac{1}{6}$
• C. $\frac{1}{3}$
• D. $\frac{2}{3}$

Answer 1

Answer: (B)

$\frac{1}{6}$

Given:

Die is thrown once

To find:

The probability of getting a multiple of 5

Total number of ways = $1,2,3,4,5,6=6$ ways

Out of these ways, multiple of 5 is $5$

Hence the number of favorable ways = 1

We know,

$P\left(\text{getting a multiple of 5}\right)=\frac{\text{No. of favourable ways}}{\text{Total no. of ways}}=\frac{1}{6}$