Question

A dichloroderivative $\left(A\right)$ on treating with $KCN$ followed by acid hydrolysis and heating gives a monobasic acid $\left(B\right)$ along with liberation of $C{O}_2$ $\left(B\right)$ on heating with liquid ammonia followed by treating with $B{r}_2/KOH$ gives $\left(C\right)$ which on treating with $NaN{O}_2$ and $HCl$ at low temperature followed by oxidation gives a monobasic acid $\left(D\right)$ having molecular mass $74$. $C$ in the whole process would be:

• A. ethyl amine
• B. propyl amine
• C. tert-butyl amine
• D. cyclopentyl amine.

Answer 1

The correct option is B propyl amine

$-CN$ group on acid hydrolysis always converts to $-COOH$

Two $-COOH$ group on one carbon atom on heating always lose $C{O}_2$ to form mono carboxylic acid.

C is propyl amine.

Option B is correct.