A die is thrown 300 times and the outcomes are noted as given below:
Outcome123456Frequency607254423933
When a die is thrown at random, what is the probability of getting a
(i) 3?
(ii) 6?
(iii) 5?
(iv) 1?
ANSWER:
Total number of throws = 300
In a random throw of a dice, let E 1 , E 2 , E 3 , E 4 , be the events of getting 3, 6, 5 and 1, respectively. Then,
(i)P(getting 3)=P(E1)=Number of times 3 appearsTotal number of trials=54300=0.18
(ii) P(getting 6)=P(E2)=Number of times 6 appearsTotal number of trials=33300=0.11
(iii) P(getting 5)=P(E3)=Number of times 5 appearsTotal number of trials=39300=0.13
(iv) P(getting 1)=P(E4)=Number of times 1 appearsTotal number of trials=60300=0.20