Question

In 50 throws of a die, the outcomes were noted as under:

$\begin{array}{ccccccc}\text{Outcomes}& 1& 2& 3& 4& 5& 6\\ \text{Number of times}& 8& 9& 6& 7& 12& 8\end{array}$

A die is thrown at random. What is the probability of getting an even number?

(a) $\frac{12}{25}$

(b) $\frac{3}{50}$

(c) $\frac{1}{8}$

(d) $\frac{1}{2}$

Answer 1

ANSWER:
(a) $\frac{12}{25}$
Explanation:
Total number of trials = 50
Let E be the event of getting an even number.
Then, E contains 2, 4 and 6, i.e. 3 even numbers.
∴ P(getting an even number) = P(E )
= Number of times even numbers appear/Total number of throws = $\frac{(9+7+8)}{50}$ = $\frac{24}{50}$ =$\frac{12}{25}$