Question

A die is thrown once. Find the probability of getting

$i)$a prime number

$ii)$a number between $2$ and $6$

$iii)$ an odd number

Answer 1

Die has $1,2,3,4,5,6$

No. of ways of getting a prime number is $2,3,5=3$

Total no. of ways$=6$

$i)$Probability (Prime no.)$=\frac{3}{6}=\frac{1}{2}$

$ii)$A no. between $2$ ad $6$ is $3,4,5=3$

$P(2<x<6)=\frac{3}{6}=\frac{1}{2}$

$iii)$Odd no.s$=1,3,5$

No. of odd no.s$=3$

P(odd no.s)$=\frac{3}{6}=\frac{1}{2}$