Question

A die is thrown once. Find the probability of getting
(i) an even number (ii) a number less than 5
(iii) a number greater than 2 (iv) a number between 3 and 6
(v) a number other than 3 (vi) the number 5.

Answer 1

A die can have outcomes as {1,2,3,4,5,6}
Total outcomes =6

(i) an even no.
{2,4,6}=3
We know that PROBABILITY = Number of favorable event / Total number of event=3/6=1/2
so, probability of an even number is 1/2.

(ii) number less than 5
{1,2,3,4}=4
We know that PROBABILITY = Number of favorable event / Total number of event=4/6=2/3

probability of number less than 5 is 2/3

(iii) number greater than 2
{3,4,5,6}=4
probability =4/6=2/3

(iv) number between 3 and 6
{4,5}=2
probability =2/6=1/3

(v) number other than 3
{1,2,4,5,6}=5
probability =5/6

(vi) Number 5
{5}=1
probability =1/6