Question

A die is thrown once. The probability of getting an odd number greater than 3 is [CBSE 2013C]


(a) $\frac{1}{3}$
(b) $\frac{1}{6}$
(c) $\frac{1}{2}$
(d) 0

Answer 1

​Total number of outcomes = 6.

Out of the given numbers, odd number greater than 3 is 5.

Numbers of favourable outcomes = 1.

∴ P(getting an odd number greater than 3) = $\frac{\mathrm{Number}\mathrm{of}\mathrm{favourable}\mathrm{outcomes}}{\mathrm{Number}\mathrm{of}\mathrm{all}\mathrm{possible}\mathrm{outcomes}}$
= $\frac{1}{6}$

Thus, the probability of getting an odd number greater than 3 is $\frac{1}{6}$.

Hence, the correct answer is option (b).