Question

A die is thrown twice. What is the probability that
$5$ will not come up either time?

Answer 1

Outcomes $=(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),$
$(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)$
$,(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)$
P($5$ will come up either times)$=\frac{25}{36}$
Explanation :- $5$ will not come up either times means In the throw no diece gets a number $5$ on them so possible outcomes
$=(1,1),(1,2),(1,3),(1,4),(1,6),(2,1),(2,2),(2,3),(2,4),(2,6),(3,1),(3,2)$
$,(3,3),(3,4),(3,6),(4,1),(4,2),(4,3),(4,4),(4,6),(5,1),(5,2),(5,3),(5,4),(5,6),$
$(6,1),(6,2),(6,3),(6,4),(6,6)$