Question

A die is thrown twice. What is the probability that at least one of the two throws comes up with the number 4 ?

Answer 1

n(E) = [(4,1),(4,2),(4,3),(4,4),(4,5),(4,6), (1,4),(2,4), (3,4), (5,4),(6,4)] = 11

n(S)= $6\times 6=36$

$p\left(E\right)=\frac{11}{36}$