wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A die is thrown two times and the sum of the scores appearing on the die is observed to be a multiple of 4. Then the conditional probability that the score 4 has appeared at least once is


A

13

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

14

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

18

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

19

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

19


Explanation for the correct option:

Step1. Define events

Total outcomes =1,1,1,2,1,3,1,4,1,5,1,6,......,5,6,6,1,6,2,6,3,6,4,6,56,6

Total number of outcomes =36

Sum obtained is multiple of 4 =A

The score 4 appeared at least once =B

Step2. Calculate the probability of Aand(AB)

A=1,3,2,2,3,1,2,6,3,5,4,4,5,3,6,2,6,6PA=936Probability=NumberoffavourableoutcomesTotalnumberofoutcomesB=1,4,2,4,3,4,4,4,5,4,6,4,4,1,4,2,4,3,4,5,(4,6)AB=4,4PAB=136

Step3. Calculate the PBA

PBA=PABPA

Substitute the required value in the formula

PBA=136936=19

Hence, Option(D) is the correct answer.


flag
Suggest Corrections
thumbs-up
10
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Questions on Compound Probability: P(A and B)
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon