Question

A die was thrown 100 times and the following observations were recorded:

Outcome	1	2	3	4	5	6
Frequency	12	18	14	26	14	16

If a die is thrown at random, find the probability of getting
(i) a number less than 3
(ii) a number greater than 4
(iii) an even number

Answer 1

Total number of trials = 100

(i) Let E₁ be the event of getting a number less than 3. Then,
P(getting a number less than 3) = P(E₁) = $\frac{\left(12+18\right)}{100}=\frac{30}{100}=\frac{3}{10}$Number of times 3 appearsTotal number of trails = 54300 = 0.18

(ii) Let E₂ be the event of getting a number greater than 4. Then,
P(getting a number greater than 4) = P(E₂) = $\frac{\left(14+16\right)}{100}=\frac{30}{100}=\frac{3}{10}$Number of times 6 appearsTotal number of trails = 33300 =0.11

(iii) Let E₃ be the event of getting an even number. Then,
P(getting an even number) = P(E₃) = $\frac{\left(18+26+16\right)}{100}=\frac{60}{100}=\frac{3}{5}$mber of times 5 appearsTotal number of trails = 39300 = 0.1
Number of times 1 appearsTotal number of trails = 60300 = 0.2