A digital timer with four digit readout is stated to have an accuracy of 0-005 percent of reading- - 1 in the final digit readout is in - s- Assuming that the instrument meets its specifications then the maximum likely error when the reading is 500 - s is - - s

The reading is = 500 μ s 0.005 percent of reading = ±0.005100× 500=0.025 μ The digit is LSD has a value of 1 μ s nbsp; ∴ Maximum error=± (0.025+1)=± ...

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A digital timer with four digit readout is stated to have an accuracy of 0.005 percent of reading, $\pm 1$ in the final digit readout is in $μ s .$ Assuming that the instrument meets its specifications then the maximum likely error when the reading is $500 μ s$ is $\pm$ ______ $μ s$

1.25

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0.125

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1.025

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0.1025

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Solution

The correct option is C 1.025
$The reading is = 500 μ s$

$0.005 percent of reading = \pm \frac{0.005}{100} \times 500 = 0.025 μ sec$
$The digit is LSD has a value of 1 μ s$

$∴ M a x i m u m e r r o r = \pm (0.025 + 1) = \pm 1.025 μ sec$

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A digital timer with four digit readout is stated to have an accuracy of 0.005 percent of reading, ±1 in the final digit readout is in μs. Assuming that the instrument meets its specifications then the maximum likely error when the reading is 500μs is ± ______ μs

The correct option is C 1.025The reading is =500μs 0.005 percent of reading = ±0.005100×500=0.025μsec The digit is LSD has a value of 1μs ∴Maximum error=±(0.025+1)=±1.025μsec

A digital timer with four digit readout is stated to have an accuracy of 0.005 percent of reading, $\pm 1$ in the final digit readout is in $μ s .$ Assuming that the instrument meets its specifications then the maximum likely error when the reading is $500 μ s$ is $\pm$ ______ $μ s$

The correct option is C 1.025
$The reading is = 500 μ s$

$0.005 percent of reading = \pm \frac{0.005}{100} \times 500 = 0.025 μ sec$
$The digit is LSD has a value of 1 μ s$

$∴ M a x i m u m e r r o r = \pm (0.025 + 1) = \pm 1.025 μ sec$