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Standard XII

Chemistry

Sulphuric Acid

A + dil. H2...

Question

(A) + dil. $H_{2} S O_{4} △ ⟶ g a s$ (B). Gas (B) turns $K_{2} C r_{2} O_{7} / H^{+}$ solution green.
Aqueous solution of (A) + $B a C l_{2} ⟶ w h i t e p p t (C)$ Filtrate after removing (C) + $B r_{2}$ water $⟶ w h i t e p p t (C)$ . Here (A), (B) and (C) are
(A) $S O_{3}^{2 -} + S O_{4}^{2 -}$ (B) $S O_{2}$ and (C) $B a S O_{4}$

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Solution

(A) is a mixture of sulphite $S O_{3}^{2 -}$ and sulphate $S O_{4}^{2 -}$
(B) is $S O_{2}$ gas and (C) is $B a S O_{4}$ .
(A) reacts with dilute sulphuric acid to liberate sulphur dioxide gas which turns acidified potassium dichromate solution green..
Sulphur dioxide reduces potassium dichromate to chromium sulphate $(C r_{2} (S O_{4})_{3})$ which is green in colour.
Barium chloride reacts with sulphate ions to form white precipitate of barium sulphate (C).
After removing (C), the filtrate contains sulphite ions.
$S O_{3}^{2 -}$ oxidized to $S O_{4}^{2 -}$ (with oxygen generated by the reaction of bromine with water) and gives white precipitate of $B a S O_{4}$ .
$B r_{2} + H_{2} O ⟶ 2 H B r + O$
$S O_{3}^{2 -} + O ⟶ S O_{4}^{2 -} ↓$

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Similar questions

S O_{3}^{2 -}

and

S O_{4}^{2 -}

both give white precipitate with

B a C l_{2}

solution. Scheme to detect

S O_{3}^{2 -}

in presence of

S O_{4}^{2 -}

is given below. If true enter 1, if false enter 0.

B a S O_{4}

is insoluble in conc. HCl while

B a S O_{4}

remains soluble. Separate

B a S O_{4}

and add

B r_{2}

water into filtrate.

S O_{3}^{2 -}

is oxidised to

S O_{4}^{2 -}

and gives white precipitate of

B a S O_{4}

Q. A gas when passes through

K_{2} C r_{2} O_{7}

and dil.

H_{2} S O_{4}

solution turns it green, the gas is:

[x] + H_{2} S O_{4} \to

[y] a colourless gas with irritating smell

[y] + K_{2} C r_{2} O_{7} + H_{2} S O_{4} \to

Green solution [x] and [y] are

Q. Colourless salt

(A) Δ \to (B) + (C)

gas

(B)

dissolves both in acid and alkali solution. Gas

(C)

turns lime water milky and acidified

K_{2} C r_{2} O_{7}

solution green. Ammoniacal solution of

(A)

gives white ppt

(D)

with

H_{2} S

gas. What is

(A)

A

and

B

are two ores of copper.

A

undergoes calcination to form a solid,

C O_{2 (g)}

and

O_{2 (g)}

B

undergoes roasting to form a solid and a gas

C

which turns acidified

K_{2} C r_{2} O_{7}

to green solution.

B

also reacts with dil

H C l

to form a solid and gas

D

which turns lead acetate solution black.

D

also reacts with

C

to form colloidal sulphur in the presence of moisture.

The gas (

C

) acts as a/an:

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(A) + dil. H2SO4△⟶gas (B). Gas (B) turns K2Cr2O7/H+ solution green.Aqueous solution of (A) + BaCl2⟶whiteppt(C) Filtrate after removing (C) + Br2 water ⟶whiteppt(C). Here (A), (B) and (C) are(A) SO2−3+SO2−4 (B) SO2 and (C) BaSO4