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Question

A dip circle, lying initially in the magnetic meridian is rotated through an angle θ in the horizontal plane, then the tangent of the angle of dip is increased in the ratio of :


A
1:cosθ
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B
1:tanθ
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C
1:cotθ
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D
1:sinθ
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Solution

The correct option is A 1:cosθ
Let δ be the angle of dip when dip circle is in magnetic meridian
tanδ=VH
The dip circle when makes an angle θ , horizontal component of the earth's magnetic field is Hcosθ
The angle of dip when not in magnetic meridian is
tanδ1=VHcosθ
tanδ1=tanδcosθ
tanδ1tanδ=1cosθ

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