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Question

A dip needle lies initially in the magnetic meridian when it shows an angle of dip θ at a place. The dip circle is rotated through an angle x in the horizontal plane and then it shows an angle of dip θ'. Then tan θ'tan θ is

A
1cos x
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B
1sin x
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C
1tan x
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D
cos x
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Solution

The correct option is A 1cos x
In first case tan θ=BVBH
Second case tan θ'=BvBHcos x
From first case and second case,
tan θ'tan θ=1cos x


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