A dip needle lies initially in the magnetic meridian when it shows an angle of dip θ at a place. The dip circle is rotated through an angle x in the horizontal plane and then it shows an angle of dip θ'. Then tanθ'tanθ is
A
1cosx
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B
1sinx
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C
1tanx
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D
cosx
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Solution
The correct option is A1cosx In first case tanθ=BVBH Second case tanθ'=BvBHcosx From first case and second case, tanθ'tanθ=1cosx