A disc is rolling (without slipping) on a horizontal surface. C is its centre and Q and P are two points equidistant from C as shown in figure. Let vP,vQ and vC be the magnitude of velocities of points P,Q and C respectively, then
A
vQ>vC>vP
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B
vQ<vC<vP
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C
vQ=vP,vC=12vP
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D
vQ=vC=vP
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Solution
The correct option is AvQ>vC>vP
Since P and Q are equidistant from the centre C, so it's ⊥ distance from the axis of rotation is also same i.e r
Considering rightwards as +vex− direction, the velocity of point P and Q on the disc can be written as: →vP=(v−rω)^i →vQ=(v+rω)^i →vC=v^i
Hence magnitude of the velocity is in order: ⇒vP<vC<vQ