A disc is rolling without slipping with angular velocity - -P- and -Q- are two points equidistant from the centre -C- The order of magnitude of velocity is

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Standard XII

Physics

Relation between Linear and Angular Speed

A disc is rol...

Question

A disc is rolling without slipping with angular velocity ' $ω$ '. 'P' and 'Q' are two points equidistant from the centre 'C'. The order of magnitude of velocity is

V_Q > V_C > V_P

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V_P > V_C > V_Q

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V_P = V_C ; V_Q = V_C / 2

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V_P < V_C > V_Q

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Solution

The correct option is A
V_Q > V_C > V_P

The rolling body will be in pure rotation with respect to its point of contact with the ground.

As V = r $ω$

v $α$ r [ $ω$ = Constant]

As $r_{Q}$ > $r_{c}$ > $r_{p}$

$\Rightarrow$ $V_{Q}$ > $V_{c}$ > $V_{p}$

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A disc is rolling without slipping with angular velocity 'ω'. 'P' and 'Q' are two points equidistant from the centre 'C'. The order of magnitude of velocity is

The correct option is A VQ > VC > VP The rolling body will be in pure rotation with respect to its point of contact with the ground. As V = r ω v α r [ω = Constant] As rQ > rc > rp ⇒ VQ > Vc > Vp

A disc is rolling without slipping with angular velocity ' $ω$ '. 'P' and 'Q' are two points equidistant from the centre 'C'. The order of magnitude of velocity is

The correct option is A
V_Q > V_C > V_P

The rolling body will be in pure rotation with respect to its point of contact with the ground.

As V = r $ω$

v $α$ r [ $ω$ = Constant]

As $r_{Q}$ > $r_{c}$ > $r_{p}$

$\Rightarrow$ $V_{Q}$ > $V_{c}$ > $V_{p}$