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Question

ANaBH4−−−PhCH=CHCHOLiAlH4−−−B

A and B are respectively:

A
PhCH=CHCH2OH,PhCH2CH2OH
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B
PhCHCH=CHCH2OH,PhCH2CH2OH
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C
PhCH=CHCH2OH,PhCH2CH2CH2OH
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D
None of these
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Solution

The correct option is B PhCH=CHCH2OH,PhCH2CH2OH
Sodium borohydride (NaBH4) reduces cinnamaldehyde via 1,2 reduction in a hydroxylic solvent to cinnamyl alcohol.
Thus, PhCH=CHCHONaBH4PhCH=CHCH2OH

But LiAlH4, being stronger reducing agent compared to NaBH4. Cinnamaldehyde undergoes 1,2 reduction with LiAlH4 to give the following reaction.

Thus, PhCH=CHCHOLiAlH4PhCH2CH2CH2OH ass shown above.

1066717_137538_ans_143886ae191b47bcb243d0420444320e.PNG

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