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Question

A distance between two consecutive nodes on a stretched string is 10 cm. It is in resonance with tuning fork of frequency 256 Hz. What is the velocity of the progressive wave in the string?

A
6.40 ms1
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B
51.20 ms1
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C
25.60 ms1
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D
12.50 ms1
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Solution

The correct option is B 51.20 ms1
Distance between two consecutive nodes = λ2λ=0.2 m.
The velocity of the progressive wave in the string is v=ν×λ=256×0.2=51.2 m/s.

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