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Standard XII

Physics

Transverse & Longitudinal Waves

A distance be...

Question

A distance between two consecutive nodes on a stretched string is $10 c m$ . It is in resonance with tuning fork of frequency $256 H z$ . What is the velocity of the progressive wave in the string?

6.40 m s^{- 1}

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51.20 m s^{- 1}

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25.60 m s^{- 1}

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12.50 m s^{- 1}

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Solution

The correct option is B $51.20 m s^{- 1}$
Distance between two consecutive nodes = $\frac{λ}{2} \Rightarrow λ = 0.2$ m.
The velocity of the progressive wave in the string is $v = ν \times λ = 256 \times 0.2 = 51.2$ m/s.

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A distance between two consecutive nodes on a stretched string is 10 cm. It is in resonance with tuning fork of frequency 256 Hz. What is the velocity of the progressive wave in the string?

The correct option is B 51.20 ms−1Distance between two consecutive nodes = λ2⇒λ=0.2 m.The velocity of the progressive wave in the string is v=ν×λ=256×0.2=51.2 m/s.

A distance between two consecutive nodes on a stretched string is $10 c m$ . It is in resonance with tuning fork of frequency $256 H z$ . What is the velocity of the progressive wave in the string?

The correct option is B $51.20 m s^{- 1}$
Distance between two consecutive nodes = $\frac{λ}{2} \Rightarrow λ = 0.2$ m.
The velocity of the progressive wave in the string is $v = ν \times λ = 256 \times 0.2 = 51.2$ m/s.