A diwali rocket is ejecting $0.05$ kg of gases per second at a velocity of $400$ m/sec. The accelerating force on the rocket is

20

dynes

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20

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22

dynes

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1000

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Solution

The correct option is C $20$ N
Momentum =mass × velocity

$\Rightarrow$ Momentum = $0.05 \times 400 = 20 k g . \frac{m}{s e c}$

$\Rightarrow$ accelerating force on the rocket $= 20$ N

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