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Question
A DNA segment has a total of 1000 nucleotides, out of which 240 of them are adenine containing nucleotides. How many pyrimidine bases this DNA segment possesses?
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Solution
(a) Cytosine and thymine are pyrimidines. As indicated by Chargaff's standard, proportion of purines to pyrimidines is equivalent.
Hence, the quantity of adenine (A) will be equivalent to the quantity of thymine (T). Number of adenine (A) containing nucleotides = 240
In this manner, A = T = 240
In this manner, A + T = 240 + 240 = 480
The quantity of cytosine (C) will be equivalent to the quantity of guanine (G).
In this way, G + C = Total number of nucleotides - Nucleotides containing An and T nitrogenous bases
= 1000 - 480 = 520
In this way, G =260, C = 260
Number of guanine will be equivalent to number of cytosine, which will be 260.
In this way, the number of pyrimidines that the portion has = C + T = 260 + 240 = 500
(a) Cytosine and thymine are pyrimidines.
As indicated by Chargaff's standard, proportion of purines to pyrimidines is equivalent.
Hence, the quantity of adenine (A) will be equivalent to the quantity of thymine (T). Number of adenine (A) containing nucleotides = 240
In this manner, A = T = 240
In this manner, A + T = 240 + 240 = 480
The quantity of cytosine (C) will be equivalent to the quantity of guanine (G).
In this way, G + C = Total number of nucleotides - Nucleotides containing An and T nitrogenous bases
= 1000 - 480 = 520
In this way, G =260, C = 260
Number of guanine will be equivalent to number of cytosine, which will be 260.
In this way, the number of pyrimidines that the portion has
= C + T
= 260 + 240 = 500
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