$A$ does $500 J$ of work in $10$ minutes and $B$ does $600 J$ of work in $20$ minutes. The power delivered by $A$ and $B$ is $P_{1}$ and $P_{2}$ respectively. Find the relation between $P_{1}$ and $P_{2}$ .

P_{1} = P_{2}

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P_{1} > P_{2}

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P_{1} < P_{2}

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P_{1}

and

P_{2}

are undefined

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Solution

The correct option is B $P_{1} > P_{2}$
Power $P = \frac{E n e r g y}{T i m e} = \frac{W o r k}{t i m e}$
$P_{1} = \frac{500}{10 \times 60} = 0.83 J / s$
$P_{2} = \frac{600}{20 \times 60} = 0.5 J / s$
$P_{1} > P_{2}$

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A does 500J of work in 10 minutes and B does 600J of work in 20 minutes. The power delivered by A and B is P1 and P2 respectively. Find the relation between P1 and P2.

The correct option is B P1>P2Power P=EnergyTime=WorktimeP1=50010×60=0.83J/sP2=60020×60=0.5J/sP1>P2

$A$ does $500 J$ of work in $10$ minutes and $B$ does $600 J$ of work in $20$ minutes. The power delivered by $A$ and $B$ is $P_{1}$ and $P_{2}$ respectively. Find the relation between $P_{1}$ and $P_{2}$ .

The correct option is B $P_{1} > P_{2}$
Power $P = \frac{E n e r g y}{T i m e} = \frac{W o r k}{t i m e}$
$P_{1} = \frac{500}{10 \times 60} = 0.83 J / s$
$P_{2} = \frac{600}{20 \times 60} = 0.5 J / s$
$P_{1} > P_{2}$