Resistors $R_{1}, R_{2}$ are connected in series. If the power dissipated by them is $P_{1}, P_{2}$ then

P_{1} : P_{2} = R_{1} : R_{2}

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P_{1} : P_{2} = R_{2} : R_{1}

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P_{1} : P_{2} = \frac{1}{R_{1}} : \frac{1}{R_{2}}

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Solution

The correct option is A $P_{1} : P_{2} = R_{1} : R_{2}$
In a series connection, the current flowing through the resistors is the same. If the current is taken as $I$ , then $P_{1} = I^{2} \times R_{1} a n d P_{2} = I^{2} \times R_{2}$
$H e n c e, P_{1} : P_{2} = R_{1} : R_{2}$ .

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