Resistors $R_{1}, R_{2}$ are connected in parallel. If the power dissipated by them is $P_{1}, P_{2}$ then

P_{1} : P_{2} = \frac{1}{R_{2}} : \frac{1}{R_{1}}

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P_{1} : P_{2} = \frac{1}{R_{1}} : \frac{1}{R_{2}}

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P_{1} : P_{2} = R_{1} : R_{2}

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Solution

The correct option is B $P_{1} : P_{2} = \frac{1}{R_{1}} : \frac{1}{R_{2}}$
In a parallel connection, the potential difference across the resistors is the same. Hence, $P_{1} = V^{2} / R_{1} a n d P_{2} = V^{2} / R_{2}$
Hence,
$P_{1} : P_{2} = \frac{1}{R_{1}} : \frac{1}{R_{2}}$

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